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on an ice rink, two skaters of equal mass grab hands and spin in a mutual cicle once every 2.5 seconds. If we assume their arms are each .80m long and their individual masses are 60kg, how hard are they pullin on one another?

2006-11-02 17:45:25 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

F = mv^2/r = mrω^2 = 60*0.8(2π/2.5)^2 = 303.1942 N

2006-11-02 18:11:17 · answer #1 · answered by Helmut 7 · 0 0

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