If a cube shape is divided into 2 equal parts, how would its surface area be divided/multiplied?

Answer 1

initial surface area=6a^2
new surface area=2[2a^2+4(a^2/2)]
=2*4a^2=8a^2
it will be 4/3 times the original surface area

Answer 2

It depends on the angle of division (i.e. the position of the plane of symmetry of the cut.)

I believe 2/3 is the factor you are looking for.

If we assume it was cut in half, parallel to two opposing sides, then each half would have 1/2 the surface area of original cube + the area of one face (the face added by the cut).

If the side of the cube has length s then the surface area of the cube = 6s^2 and the surface area of the half-cube is therefore

3s^2 +s^2 = 4s^2 = 2/3 of the original cube. The suface area of the 2 halfs together will be 4/3 of the origin

Answer 3

it depends on the angle of the cut. it will have a greater surface area then a cube but if you cut at a right angle to the sides it will increase less than if you were to cut diagonally from corner to corner. then there is the possibility that you could cut irregularly and increase it even more. in theory if you could cut infinitely thinly you could end up with infinite surface area.

Answer 4

Cube has all sides equal.
Area of cube = (a * a) multiply by 6 (there are 6 faces)
Area = 6a^2

Dividing the shapeby , therefor area divides by 2
Area/2 = (6a^2)/2

Area = 3a^2

Answer 5

E = mCquadrupled + x - alpharomeo