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Encuentre un Yp particular de la solución de la ecuación dada

2006-11-02 17:08:35 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

y" + y = 1

1=sin(x) + xcos(x)

Equation should read 1=sin^2(x) + xcos^2(x)
and x value is elements of real numbers.

2006-11-02 17:12:52 · answer #1 · answered by prashmanic 4 · 0 1

y(x) = Ao + A1 x + A2 x^2 + A3 x^3 + A4 x^4 + ....

y''(x) = 2 A2 + 6 A3 x + 12 A4 x^2 + ....

sin(x) = x - (x^3 / 3!) + (x^5 / 5!) - (x^7 / 7!) + (x^9 / 9!) -....

x cos(x) = x - (x^3 / 2!) + (x^5 / 4!) - (x^7 / 6!) + ....

Add each side and equate coefficients to get the particular solution.

2006-11-03 01:26:41 · answer #2 · answered by z_o_r_r_o 6 · 0 0

note that Y" usually means the antiderivative of the second derivative of y. ie Y"=y'

2006-11-03 01:16:58 · answer #3 · answered by nemahknatut88 2 · 0 0

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