i need to find the derivative of the sqrt of (25-x^2). i keep screwing up. thanks for your help.
2006-11-02 16:59:42 · 5 answers · asked by Slevin Kelevra 2 in Science & Mathematics ➔ Mathematics
-x/ sqrt (25-x^2)
ill explain it for ya
just a chain rule problem
the equation is easy written as (25-x^2)^(1/2)
(1/2) goes to (-1/2) dropping (25-x^2) to the denominator
and multiplying by (1/2)
next times the numerator by the derivative of the inside (-2x)
the -2x and 1/2 make -x in the numerator
leaving -x/(25-x^2)^(1/2) which is another way of what i typed for teh answer
2006-11-02 17:01:28 · answer #1 · answered by RichUnclePennybags 4 · 0⤊ 0⤋
(25-x^2)^.5 - use chain rule
.5(25-x^2)^(1-.5) * (-2x) =
-x ( 25-x^2)^-.5 or
-x over sqrt (25-x^2)
2006-11-02 17:04:15 · answer #2 · answered by iggry 2 · 0⤊ 0⤋
sqrt of (25-x^2) = (25-x^2)^(0.5)
0.5 mutiply by (25-x^2)
= 12.5 - 0.5x^2
The above answer is accepted in the exams as it is the most simplified.
2006-11-02 17:06:48 · answer #3 · answered by prashmanic 4 · 0⤊ 0⤋
sqrt(25x^2) = (25x^2)^1/2
1st derivative = 1/2*50*x*(25x^2)^(-1/2)
=10, -10
2006-11-02 17:43:33 · answer #4 · answered by collegesniper 2 · 0⤊ 0⤋
y=sqrt(25-x^2)
y'=(1/2)(25-x^2)^(-.5)*(-2x)=-x/sqrt(25-x^2)
2006-11-02 17:30:34 · answer #5 · answered by yupchagee 7 · 0⤊ 0⤋