Find y^n in the following( second derivative): y=sin(x^2.e^x)?

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please answer this soon. . thanks

2006-11-02 16:41:29 · 2 answers · asked by tyshea 1 in Science & Mathematics ➔ Mathematics

y'=cos(x^2e^x)(2xe^x+x^2e^x)

y''=-sin(x^2e^x)(2xe^x+x^2e^x)^2+
(2(e^x+xe^x)+(2xe^x+x^2e^x))cos(x^2e^x)

2006-11-02 16:46:17 · answer #1 · answered by Greg G 5 · 0⤊ 0⤋

(x^2+4x+2)*e^x*cos(x^2*e^x)
..-x^2*(x+2)^2*e^(2x)*
....sin(x^2*e^x)
sry the format split it

2006-11-02 16:45:44 · answer #2 · answered by RichUnclePennybags 4 · 0⤊ 0⤋