how do you factor this equation?

Question

1. w^2+1-36g2
2. 4a^2=17a+15 what is the solution set
3.128c^3+54q^3
4. n^3-2n^2-n+2=0
5. (x+9)(x-3)=(2x+4)(x-3)

Answer 1

1. w^2+1-36g^2 = (w-6g)^2 +1

2. 4a^2 - 17a - 15 = 0 what is the solution set
x = (17 ± √(289 +240))/8
x = (17 ± √(529))/8
x = (17 ± 23)/8
x = (5,-3/4)

3.128c^3+54q^3 =
2((4c)^3 + (3q)^3)

4. n^3 -2n^2 -n + 2=0
n^2(n-2) - (n - 2) = 0
(n^2 - 1)(n - 2) = 0
(n + 1)(n - 1)(n - 2) = 0
n =(-1,1,2)

5. (x+9)(x-3)=(2x+4)(x-3)
2x = 5
x = 5/2