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Take the antiderivative of e^(pix^2) from the interval negative infinity to positive infinity.

2006-11-02 15:45:00 · 4 answers · asked by petswodahs 1 in Science & Mathematics Mathematics

4 answers

The antiderivative is:

(1/2)erfi(sqrt(pi)*x)

I used Wolfram

2006-11-02 15:48:46 · answer #1 · answered by JSAM 5 · 1 1

positive infinity

2006-11-02 16:15:54 · answer #2 · answered by RichUnclePennybags 4 · 1 0

positive infinity

2006-11-06 13:43:46 · answer #3 · answered by MsMath 7 · 0 1

there is no antiderivative
In other words, there is no function F(x) such that
F'(x) = e^(pix^2)
s

2006-11-02 16:13:42 · answer #4 · answered by Anonymous · 0 2

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