A 0.100 kg ball is thrown straight up into the air with an initial speed of 15.0 m/s. Find the momentum of the ball (a) at its maximum height, and (b) halfway up to its maximum height.
2006-11-02 15:24:36 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Physics
a) zero momentum, as velocity on top is zero. p=mv
p=0.100kg * Om/s
b) Vf = Vi + at
0=15+(-10)t
t=1.5ec (to reach maximum height)
Divide by 2 for halfway up .i.e 0.75ec
Vf = Vi + at
O=15 + (-10)(0.75)
Vf = 7.5m/s
p=mv (p = momemtum)
p = (0.100kg)(7.5m/s)
p = 0.75kg*m/s, upwards (Direction is important)
2006-11-02 15:34:31 · answer #1 · answered by prashmanic 4 · 1⤊ 0⤋
At the ball's maximum height its velocity is zero so its momentum is also zero.
At half the maximum height its velocity is v=u+2gh.
Momentum will be mv.
2006-11-03 06:56:34 · answer #2 · answered by Napster 2 · 0⤊ 0⤋
wow good question. hmm..
2006-11-02 23:27:24 · answer #3 · answered by pacificsun03 1 · 0⤊ 1⤋
answer my question http://mx.answers.yahoo.com/question/index;_ylt=Aizf0V8SmYf4FC.4wLDnR_WY8gt.?qid=20061102194837AAZg9H5
2006-11-02 23:25:57 · answer #4 · answered by ? 2 · 0⤊ 0⤋
Duh I doe no
2006-11-02 23:49:25 · answer #5 · answered by gumball421 2 · 0⤊ 0⤋