three particles have identical masses. Each particle experiences only the gravitational forces due to the othertwo particles. How should the particles be arranged so each one experieces a net gravitational force that has the same magnitude? Why?
2006-11-02 15:14:48 · 6 answers · asked by FIGUREsk8er4life 1 in Science & Mathematics ➔ Physics
Draw a triangle, an equilateral triangle, that is : each angle is 60 degrees. Each particle is placed at the vertex.
2006-11-02 15:24:10 · answer #1 · answered by chanljkk 7 · 2⤊ 0⤋
What you are saying is the 3 particles are the same type of particle (or their mass would not be the same). They would have to be in a triangle to excert the same amount of net gravity on each other. If any 2 are closer then the 3rd, the net gravitaional force would not be the same as gravity is a combination of mass & distance to its mass.
2006-11-02 15:28:19 · answer #2 · answered by Anonymous · 1⤊ 0⤋
The particles should be arranged in the form of an equilateral triangle. Rest is self explanatory.
2006-11-02 22:59:03 · answer #3 · answered by Napster 2 · 0⤊ 0⤋
in a triangle so that each experiances the gravitational force of two others on each side of it they will all be equal then
2006-11-02 15:23:16 · answer #4 · answered by soccerbabe_angel 3 · 0⤊ 0⤋
An equilateral triangle so the distances and masses are the same.
2006-11-02 15:23:06 · answer #5 · answered by shmux 6 · 1⤊ 0⤋
The placement has to be symmetrical to maintain symmetry in the forces. What 3-pointed object has that kind of symmetry?
2006-11-02 15:17:25 · answer #6 · answered by arbiter007 6 · 0⤊ 0⤋