merry go round?

Question

can anyone help me do this?
A child on a merry-go-round is moving with a speed of 1.05 m/s when 1.20 m from the center of the merry-go-round.
(a) Calculate the centripetal acceleration of the child.
m/s2 = --Direction-- toward the center away from the center tangent to the circular path
(b) Calculate the net horizontal force exerted on the child (mass = 25.0 kg).
N --Direction-- toward the center away from the center tangent to the circular path

Answer 1

a) a=v^2/r
=1.05^2/1.2
=0.92m/s^2 toward the center

b)F=ma
=25*0.92
=23N toward the center.

Pls memorize the above formulas. You need them if you want to be able to solve circular motion problems. The meaning of each term is given in your textbook. The direction of acceleration and force is also given in your textbook. If you don't understand the explanation in your textbook, then go to Yahoo again for clarification.

Answer 2

Centripetal acceleration = v^2/r

-----------> (1.05)^2/1.2 = 0.92 m/s^2

Centripetal force = m*a

------------>(25)(0.92) = 22.97 N

Hope this helps