If a house cost $1,682 in 1844, and the same house cost $122,776 now, what is the percentage of increase?

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If a house cost $1,682 in 1844, and the same house cost $122,776 now, what is the percentage of increase?

2006-11-02 13:17:34 · 3 answers · asked by Mimi. 3 in Science & Mathematics ➔ Mathematics

3 answers

Solve the equation:

(Price increase)/(Original Price) x 100

Plugging in our values, you get:

(122776 - 1682)/(1682) x 100

Solving for x, you get x = 7200% increase

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Hope this helps

2006-11-02 13:19:53 · answer #1 · answered by JSAM 5 · 0⤊ 1⤋

7199.41% increase

proof
increase=122776-1682
% increase= increase/original(1682)

the people before forgot that it is increase and gave the percent difference

2006-11-02 21:20:51 · answer #2 · answered by lekhaj5 2 · 0⤊ 1⤋

122,776/1682 is 72.99... the increase is 729.9%

PS please award best answer

2006-11-02 21:20:14 · answer #3 · answered by WhizMaster 4 · 0⤊ 1⤋