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what are the first 5 numbers if you:

1. "start at 10,double the number before this one,and subtract 1".

2. "start at 2, triple each number and add 1".

2006-11-02 12:11:05 · 5 answers · asked by kogmu 3 in Science & Mathematics Mathematics

5 answers

1. 2(n-1) -1= x, where n starts as 10 then n-1 will be equal to 9 and then becomes your answer, or x. 2(9)-1=17, then n is 17 the second time you use this equation....the first 5 numbers are 17, 31, 61, 121, 241. each answer is one less than one less twice the number before it, confirming our equation.

2. 3n+1=x, where n starts as 2. The answers are 7, 22, 67, 202, 607. each number is triple the number before it, plus one.......

sorry if my answers are wrong.......

but hope this is correct because it is very familiar to me.......it is like an IQ test...

2006-11-03 23:53:35 · answer #1 · answered by Anonymous · 0 0

The equations you need are:

1. 2(n-1) -1= x, where n starts as 10 (so n-1 would equal 9) and then becomes your answer, or x. 2(9)-1=17, so n is 17 the second time you run through the equation. Therefore, the first 5 numbers are 17, 31, 61, 121, 241. Note that each answer is one less than one less twice the number before it, confirming our equation.

2. 3n+1=x, where n starts as 2. The answers are 7, 22, 67, 202, 607. Note how each number is triple the number before it, plus one.

2006-11-02 12:19:15 · answer #2 · answered by vtpoetchic 2 · 0 0

Hi. Reason it out. Start at 10, then double the number before (9) to get 18, then subtract 1. The second one does not make sense to me.

2006-11-02 12:15:46 · answer #3 · answered by Cirric 7 · 0 0

17, 31, 59, 115, 229

7, 22, 67, 202, 607

2006-11-02 12:14:01 · answer #4 · answered by robtheman 6 · 0 0

1. 10X10-1=99
2. 2X2X2+1=9

2006-11-02 12:15:46 · answer #5 · answered by Jackie 2 · 0 0

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