HELP ME!! Calculate the density, g/cm3, of propane C3H8 at 95.0oC and 874 torr.?

Question

Calculate the density, g/cm3, of propane C3H8 at 95.0oC and 874 torr.

Remember, to enter an answer in exponential notation use e, example: 1.47e-8

HELP ME!!

Answer 1

Answer: Density = 0.00168g/cm^3

Using PV = nRT derive ---> MM*P*V / RT = m
Convert 95 deg C to K (+273K) ---> 368K
Convert 874 torr to atm (1atm/760torr) ---> 1.15atm
Set volume as 1cm^3 = 0.001L

Find mass using MM*P*V / RT = m

(44.08g/mol)(1.15atm)(0.001L)/(0.0821atmL/molK)(368K) = 0.00168g

Since Density in this case is g/cm^3
D = 0.00168g/cm^3