True
An isosceles triangle is defined as a triangle which has two equal angles. It doesn't say it has to be exactly two.
2006-11-02 11:30:45
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answer #1
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answered by MsMath 7
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It is true-- an isosceles triangle is a triangle with AT LEAST 2 sides of equal length. Because an equalateral triangle has 3 (which is still more than 2), then the statement is true.
2006-11-04 12:29:23
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answer #2
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answered by David W 4
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An isosceles triangle has two of its sides equal. An equilateral triangle has all sides equal. Obviously, two of its sides are equal. So, it can be called an isosceles triangle.
The statement is true.
2006-11-02 11:56:56
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answer #3
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answered by Akilesh - Internet Undertaker 7
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All equilateral triangles are isosceles, but not all isosceles triangles are equilateral.
Your statement is true.
2006-11-02 11:43:42
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answer #4
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answered by Anonymous
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true
but an isosceles triangle is NOT an equilateral triangle
2006-11-02 11:32:23
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answer #5
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answered by sweetchik5188 2
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false. an equilateral triangle has all angles equal to 60 degree. but an isosceles triangle cannot have all three angles equal to 60 degree. If they are, it is not isosceles triangle but it is equilateral triangle.
2006-11-03 18:27:44
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answer #6
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answered by Amandeep 1
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this statement is true..
all the equilateral triangles are isosceles..but not isosceles triangles are not equilateral triangles...(never ever)...
2006-11-02 11:54:57
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answer #7
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answered by shandanger 1
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an isosceles triangle is a triangle with at LEAST 2 sides equal, so yes.
You can also have a right isosceles triangle.
2006-11-02 11:50:08
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answer #8
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answered by Sherman81 6
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this is true, becuase an isosceles triangle is AT LEAST 2 sides of the triangle are congruent.
2006-11-02 11:49:36
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answer #9
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answered by martinashasha 2
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If you think it sounds a little odd, I'd agree with you. However, it works out better this way, since you don't want to have to deal with exceptions when you are doing proofs. It's similar to why we say a square is a type of rectangle or parallelogram, or a circle is a type of ellipse.
2006-11-02 12:04:19
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answer #10
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answered by Anonymous
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