An object with a mass of 30 kg is on an inclined surface. The Normal force exerted on the object is 250 N.
a) What is the gravitational force?
b) Tangential?
c) Angle of Incline?
d)Acceleration of Object?
2006-11-02 11:06:29 · 5 answers · asked by Tennis2127 2 in Science & Mathematics ➔ Physics
a) W = mg = 30*9.90662 = 294.1986 N
b) Ft = 294.1986sinθ = 155.0897 N
c) cosθ = 250/294.1986, θ = 31.81376°
d) a = 155.0897/30 = 5.19657 m/sec^2
2006-11-02 11:17:28 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋
a) w=mg=30 * 9.8 =294 N
b)Tangential force = Ft=(w^2 - Fn ^ 2)^0.5 =154.7 N
c)The Normal force =Fn =w cos A
250 = 298 cos A
cosA =
Angle of Incline=A=
d) if there is no frictional force:
Acceleration of Object=a=g * sin A
2006-11-02 19:50:04 · answer #2 · answered by Ormoz 3 · 0⤊ 0⤋
a) 9.81m/s2 (approx 300N)
b) ?
c) ?
d) ?
Ok, we couldn't really help, but it really needs a diagram. Sorry
2006-11-02 19:09:51 · answer #3 · answered by katiemigs 1 · 0⤊ 0⤋
no i need help with MY physics homework.
2006-11-02 19:08:15 · answer #4 · answered by Anonymous · 0⤊ 0⤋
d) 8.33
2006-11-02 19:11:20 · answer #5 · answered by Vladimir S 2 · 0⤊ 0⤋