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i need help!!!
if a force (F1) acts upon a block of 5kilograms, in the east direction and another force (F2) acits upon the block but towards the west direction. how much is the acceleration using the f=ma equation.
.................force(F1) = 19 Newtons.....................
force(F2) = 25 Newtons..................
mass of block = 5 kilograms

2006-11-02 10:29:18 · 4 answers · asked by FIGUREsk8er4life 1 in Science & Mathematics Physics

4 answers

The net force is F2 - F1 = 25 - 19 = 6N.

From F = ma, a = F/m = 6/5 = 1.2 m/s^2, toward the west because F2 > F1. Also, we're ignoring friction.

2006-11-02 10:44:10 · answer #1 · answered by bpiguy 7 · 0 0

Make a triangle and put a F for force and inside top of triangle and put m on one side and a on the other m for mass and a for acceleration. then put a line between the m and a in the triangle( the letters should be inside the triangle near the pionts).
like this (sort of)

F
----------
a | M the --- mean divide the | mean times

cover what you are trying to fing and thats what you do to find it.
so it would be A= F/M A= 25/5 A=5 grams

2006-11-02 18:47:39 · answer #2 · answered by ♥Confused♥ 4 · 0 0

first calculate sum of the two force vectors:
F=F1+F2 (this is a vector sum)
f=magnitude of F
f1=magnitude of F1
f2=magnitude of F2
f=(f1 ^ 2 + f2 ^ 2) ^ 0.5
f=31.4
a=f/m
a=6.28

I AM VERY SORRY, I MISREAD THE QUESTION AND SO MY ANSWER IS INCORRECT.

THE CORRECT ANSWER IS:
f=f2-f1=26-16=6 N
a=f / m = 6/ 5 = 1.2 m/s^2

2006-11-02 18:37:18 · answer #3 · answered by Ormoz 3 · 0 0

Solve for the resultant force first: F=25N(F2)-19N(F1)=6N

Solve for the acceleration: a=F/m=6N/5kg=1.2m/s^2 towards the west

2006-11-02 18:37:40 · answer #4 · answered by Darrick B 2 · 0 0

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