algebra!!!!!!!!?

Question

help me.

write the slope form of an equation of the line that passes through each pair.
(-1,-7), (1,3)

Answer 1

slope = 3-(-7) / 1-(-1) = 10/2 =5
y-3= 5(x-1)

s

Answer 2

Kimberly,

You must use the slope formula, which reads:

(y2 - y1)/(x2 - x1) = slope = m

Keep in mind that m = slope.

For the point (-1,-7), x1 = -1 and y1 = -7

Got it? See it?

For the point (1,3), x2 = 1 and y2 = 3

Got it? See it?

Now, we simply plug those numbers into the formula to find the slope.

slope = 3 -(-7)/1 -(-1)

slope = 10/2

slope = 5

Guido

Answer 3

Slope: m = (3 - (-7))/ (1-(-1)) = 5

y-intercept: b = -7 - (5*-1) = -2
Equation: y = 5 x + (-2)

Answer 4

the easiest way to do line is to find the gradient and call it 'm'.
Then, if it goes through the point (a,b), the line has equation:
y-b = m(x-a)

So in this case, the gradient is (3--7)/(1--1) = 10/2 = 5
It goes through (1,3)
so the equation is:
y-3 = 5(x-1)
or, if you prefer, y = 5x - 2

nycfunction's answer is hilarious, but it doesn't answer the question.

Answer 5

slope = y2-y1 / x2-x1

so:

slope = 3 - -7 / 1- -1 = 10/2 = 5

Answer 6

y = mx + b where m = slope and b = y-intercept

slope = m = rise / run

using your two points:

rise = change in y = 10
run = change in x = 2
m = 10/2 = 5

y = 5x + b so use either point to solve for b, substituting x and y:

3 = 5(1) + b
3 = b + 5
b = -2

y = 5x - 2

Answer 7

this is y=5x-2

so this slope goes through (0, -2) and (2/5 ,0)

Answer 8

y2-y1/x2-x1

3--7/1--1
10/2
5 = slope