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When making a batch of the mertial, you must add the proper amount of a .36 M sodium sulfate solution to precipitate all the barium in 5.00 L of a 0.15 M barium nitrate solution. Teh reaction occurs as follows:
Na SO (aq) + Ba(NO ) (aq)----> 2 NANO (aq) +
2 4 3 2 3
BaSO (s)
4
The lower numbers go halfway between the letters.

2006-11-02 09:40:12 · 2 answers · asked by ShanAnn B 1 in Science & Mathematics Chemistry

2 answers

Na2SO4 (aq) + Ba(NO3)2 (aq) --> 2 NaNO3 (aq) + BaSO4 (s)

The moles of Barium = 5.00 L * 0.15 mol/L = 0.75 moles

This is also the moles of sulfate needed:

0.75 mol / 0.36 mol/L = 2.08 L of Na2SO4

2006-11-02 16:07:20 · answer #1 · answered by Richard 7 · 66 0

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2016-12-28 11:17:13 · answer #2 · answered by frahm 3 · 0 0

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