Each base is 90' apart
2006-11-02 09:38:13 · 8 answers · asked by Levi M 1 in Sports ➔ Other - Sports
~multiply the distance between first base and home plate by itself, then multiply the distance between second base and first base by itself and add the two products together. The square root of the result is equal to the distance between home plate and second base. Or so says Pythagoras. It's like, you've got nine Indian children on a tiger skin, sixteen on a lion skin and five Indian women on a hippopotomus skin. The squaws on the hippopotomus is equal to the sons of the squaws of the other 2 hides.
2006-11-02 09:53:32 · answer #1 · answered by Oscar Himpflewitz 7 · 1⤊ 0⤋
In a 40 5 40 5 ninety degree triangle, the climate are in a ration of a million:a million:a million^a million/2, so the respond is ninety circumstances the sq. root of two, or approximately 127.28 feet. it relatively is an identical utilising the Pythagorean theorem. (ninety^2 + ninety^2) = x^2, that's additionally 127.28 feet. the area from domicile to 2d is comparable to first to a minimum of one/3.
2016-11-27 00:13:16 · answer #2 · answered by Anonymous · 0⤊ 0⤋
127 feet and 3 3/8 inches from the back of home plate (foul territory) to second base.
2006-11-02 09:42:03 · answer #3 · answered by Jason W 4 · 1⤊ 0⤋
its the hypotenuse of the right triangle. a^2 + b^2 = c^2. pythagorean man
2006-11-02 09:41:35 · answer #4 · answered by foxfire101 4 · 0⤊ 0⤋
LOL 90 foot bases... you answered your own damn question.
2006-11-02 10:19:55 · answer #5 · answered by Anonymous · 0⤊ 0⤋
It should be 180 feet.
2006-11-02 09:41:08 · answer #6 · answered by acornone1988 2 · 0⤊ 0⤋
An eternity away...
2006-11-02 09:40:15 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Acording to you then, its 180ft.
2006-11-02 09:41:47 · answer #8 · answered by Anonymous · 0⤊ 0⤋