the blades in a blender rotate at a rate of 6500rmp.
when the motor is turned off durinf operation, the blades slow to rest in 3,0s what is the angular acceleration as the blades slow down?
2006-11-02 09:32:41 · 3 answers · asked by nice_ girl 1 in Science & Mathematics ➔ Physics
First convert rpm to rad/s:
6500 rot/m x (2pi rad/rot) x (1m/60s)=680.68 rad/s
angular acceleration (alpha)= [w(f)-w(o)]/t=
[0-680.68 rad/s]/3s=-226.89 rad/s^2
2006-11-02 09:48:39 · answer #1 · answered by Darrick B 2 · 4⤊ 0⤋
For constant angular acceleration, a = (change in rpm) divided by time, so for your problem, a = 6500 over 3 = 2167 rpm per second is the angular acceleration. This is not a standard unit; more common is radian per sec^2 for which you have to take the above and multiply by 2pi over 60---> 226.93 rad per sec^2
2006-11-02 09:40:38 · answer #2 · answered by Steve 7 · 0⤊ 0⤋
lets use the formula:
w = w(0) + (alpha)*t
where w is the final angular velocity = 0 and alpha is the angular accelleration
t = 3.0s
w(0) is the initial angular velocity =6500rpm = 680.7rad/s
0 = 680.7rad/s + (alpha)*3.0s
alpha(ang. accelleration) = - 680.7/3.0 = 227rad/s^2
2006-11-02 10:00:33 · answer #3 · answered by quark_sa 2 · 0⤊ 0⤋