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Write the standard form of an equation of the line that passes through the given point and has the given slope.
(-7,2), slope=6
please helppp!!!!

2006-11-02 09:24:15 · 11 answers · asked by kimberly 1 in Science & Mathematics Mathematics

11 answers

okay your slope is 6
so plug int he x's and why's
y = mx +b
2 = 6(-7) + b
2 = -42 + b
44 = b
y = 6x + 44

2006-11-02 09:27:08 · answer #1 · answered by abbs 2 · 0 0

Use the point-slope formula.
m = slope.
Our slope is 6 as given.
Our point is (-7, 2).
Plug that into y - y1 = m (x - x1)

y - 2 = 6(x -(-7))

y - 2 = 6 (x + 7)

Next:

Multiply each term inside the parentheses on the right side of the equation by the outside number 6.

We now have this:

y - 2 = 6x + 42



Add 2 to BOTH side of the equation.

You get this:

y = 6x + 44

Final answer: y = 6x + 44

2006-11-02 09:32:47 · answer #2 · answered by kum-Bucket69 2 · 0 0

You are given a point and the slope.

Use the point-slope formula.

m = slope.

Our slope is 6 as given.

Our point is (-7, 2).

Plug that into y - y1 = m (x - x1)

LOOK:

y - 2 = 6(x -(-7))

y - 2 = 6 (x + 7)

Next:

Multiply each term inside the parentheses on the right side of the equation by the outside number 6.

We now have this:

y - 2 = 6x + 42

See it?

Next: Add 2 to BOTH side of the equation.

We get this:

y = 6x + 44

Final answer: y = 6x + 44

Guido

2006-11-02 09:29:23 · answer #3 · answered by Anonymous · 0 0

First realize the the standard equation of a line is:
y = mx + b
Next, realize you already have 3 of the 4 variables.
For (-7,2) x = -7 and y = 2 For Slope = 6, m = 6, all we have to do is solve for b

2 = 6(-7) + b
2 = -42 + b
44 = b

Now, to get the equation of the line, only enter in m and b and do not enter in x and y into the equation of a line.

So you will get the following:
y=6x+44

I hope this helps.

2006-11-02 10:43:22 · answer #4 · answered by Anonymous · 0 0

There's a couple of ways to do this. I will use the form
Y-y=m(X-x)
Y-2=6(X- -7)
Y-2=6(X+7)
Y-2=6X+42
6X+42=Y-2
6X=Y-44
6X-Y=-44

2006-11-02 09:28:40 · answer #5 · answered by mom 7 · 0 0

First you write it in point-slope form:
y-2=6(x+7)
Now you convert that equation into standard form:
y-2=6x+42
y-6x=44
6x-y=-44

2006-11-02 09:28:56 · answer #6 · answered by Pascal 7 · 0 0

y = mx + b where m = slope and b = y intercept

2 = -42 + b
b = 44

y = 6x + 44

2006-11-02 09:27:10 · answer #7 · answered by disposable_hero_too 6 · 0 0

Okay, put in y=mx+b form, 2=(6*-7)+b, and just solve for b!
Then just put in y=6x+b!

2006-11-02 09:32:47 · answer #8 · answered by yljacktt 5 · 0 0

y-6=2(7+X)
Y-6=14+2X
Y=8+2x

I think thats it. Its been awhile since my algebra days.

2006-11-02 09:28:02 · answer #9 · answered by Me 2 · 0 0

(x - y^5)^3 = x^3 - 3x^2y^5 + 3xy^10 - y^15

2016-05-23 21:07:31 · answer #10 · answered by Heather 3 · 0 0

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