[1 mole of a gas occupies a volume of 24.0dm at rtp.Calculate the mass of hydrogen peroxide that decomposed?

Question

after 4 minutes.
Relative atomic mass H=1,0=16.

2]Using 0.3 mol dm hydrogen peroxide.Give one reason for the answer if it were to be carried out as a experiment.Please show working cause i don't really understand it.

Answer 1

The balanced equation for the reaction is:

2 H2O2 --> 2 H2O + O2

1] If one mole of Oxygen is produced, the 2 moles of Hydrogen peroxide would be needed. One mole of Hydrogen peroxide contains 2*H + 2*O = 2(1) + 2(16) = 2 + 32 = 34 grams.

2 moles of Hydrogem peroxide = 2*34 grams = 68 grams.

2] Is it 0.3 moles or 0.3 cubic decimeters of Hydrogen peroxide?

Assuming 0.3 moles, then from the above, 0.15 moles of Oxygen would be produced. The volume would be:

0.15 moles * 24 cubic dm/mole = 3.6 cubic dm of Oxygen at rtp.

Answer 2

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