To answer this I must first explain what an equation is:
An equation is where 2 sides are equal to one another. Ex. 4x + 13 = -91
An expression does not have the = sign. Example: 4x + 13
2006-11-02 08:24:50
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answer #1
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answered by T'Vral 3
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An expression is a combination of numbers, operators, grouping symbols (such as brackets and parentheses) and/or free variables and bound variables arranged in a meaningful way which can be evaluated. Bound variables are assigned values within the expression (they are for internal use) while free variables can take on values from outside the expression.
For a given combination of values for the free variables, an expression may be evaluated, although for some combinations of values of the free variables, the expression may be undefined. Thus an expression represents a function whose inputs are the values assigned the free variables and whose output is the resulting value of the expression.
For example, the expression
x / y
evaluated for x = 10, y = 5, outputs the number 2; but is undefined for y = 0.
The evaluation of an expression is dependent on the definition of the mathematical operators and on the system of values that is its context.
Two expressions are said to be equivalent if, for each combination of values for the free variables, they have the same output, i.e., they represent the same function.
2006-11-02 08:24:50
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answer #2
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answered by campkid4ever 2
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Any expression that represents a numeric value by using combination of numbers, operators, grouping symbols
2006-11-02 08:26:47
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answer #3
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answered by Up_In_Smoke 2
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a million/2 + a million/2 = finished 2 people who're extremely meant to be at the same time make themselves experience finished. people around you notice and ask "the place's your different a million/2?" once you're actually not at the same time. you experience like a million/2 of you is lacking once you're aside.
2016-12-28 11:09:09
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answer #4
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answered by ? 3
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it's an equation without the = sign, so it can only be simplified.
ex. 5y+6-5y
2006-11-02 08:24:12
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answer #5
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answered by Anonymous
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