A) Ca(s) Ca2+(aq)
B) Hg(I) Hg2+(aq)
C) Fe+2(aq) Fe3+(aq
D) NO3- (aq) NO(g)
E) SO3 2-(aq) SO4 2-(aq)
2006-11-02 08:07:28 · 2 answers · asked by help_w_homeowrk 1 in Science & Mathematics ➔ Chemistry
REDUCTION means charge is reduced, so that means it goes more negative, down in value, etc.
oxygen is -2, except in peroxide, which isn't here, so it's -2.
A and B are C are out of the question, they got more positive.
In E) SO3^2- (sulfite) sulfur has an oxidation state of -2=-6+S, S=+4. In SO4^2- (sulfate) sulfur has an oxidation state of -2=-8+S, so S=+6. It went from +4 to +6, this isn't your answer.
In D) the oxidation state of N in NO3^- (nitrate) is +5. So -1=-6+N and N would equal +5. In the NO(g), the oxidation state of N is given by 0=-2+N. N= +2. D is your answer, charge decreased from +5 to +2.
2006-11-02 08:17:44 · answer #1 · answered by calcu_lust 3 · 1⤊ 0⤋
I think it's,
G) Genocide
2006-11-02 17:37:27 · answer #2 · answered by Anonymous · 0⤊ 1⤋