Math halp..Solve and tell me hoe to get it?

Question

A car leaves a town at 44 miles per hour. Two hours later, a second car leaves the same town traveling the same route and overtakes the first car in 5 hours and 30 minutes. How fast was the second car traveling?

Enter your answer as a number without the units.

Answer 1

The first car has been traveling for 7.5 hours, so it has covered 330 miles; therefore the second car has been traveling at 330 miles/5.5 hours=60 miles per hour.

Answer 2

OK, think of it this way. How long was it between when the first car left and when they passed? 2:00 + 5:30 = 7:30 hours. The car was travelling 44 miles per hour, so in 7 1/2 hours, it travelled 330 miles. The second car travelled the same distance, 330 miles, in only 5 1/2 hours. So if it travelled 330 miles in 5.5 hours, just divide 330 by 5.5 to get the speed in miles per hour. Final answer: 60 mph.

Answer 3

At the point that Car 2 overtakes Car 1, there has been 7 1/2 hours pass. To find the distance where this happens, use the equation: distance travelled = velocity Car1 x 7 1/2 hours distance = 44 mi/hr x 7 1/2 hr. = 330 miles total travelled

To find the velocity of Car 2, use the equation: V = d / t

V = 330 miles / 5 1/2 hours = 60 mi/hr for Car 2

Answer 4

When the first car is being passed, it has been traveling for 7.5 hours at 44 miles/hour. Multiply those together to get 330 miles. The second car travels the same distance in 5.5 hours. Divide 330 miles by 5.5 hours to get 60 miles/hour.

Answer 5

1st car travelled 7 1/3 hrs at 44 mph=322 2/3 miles
2nd car travels 322 2/3 miles in 5 1/3 hrs
(968/3)/(16/6)=968/16=242/4=121/2=60.5

Answer 6

I think you need more English help! lol