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A sidewalk a = 4 feet wide surrounds a rectangular plot of ground that measures b = 75 feet by c = 80 feet. Find the area of the sidewalk.

Enter the answer as a number without the units.

How do you get the answer

2006-11-02 06:44:48 · 11 answers · asked by Me 6 in Science & Mathematics Mathematics

11 answers

this would be easier to see if we could draw on here, so bear with me.

The sidewalk is a series of 4 rectangles, each 4' wide and of varying lenghts, to surround the plot of 75' x 80'

the four rectangles then are of lenthgs 75, 75, 80, 80.

This would leave 4' x 4' squares at each corner.

So the area would be:

75*4 + 75*4 + 80*4 + 80*4 + 4*4 + 4*4 + 4*4 + 4*4 = 1304 sq ft

2006-11-02 06:49:01 · answer #1 · answered by disposable_hero_too 6 · 2 0

Draw a diagram
divide the sidewalk into 4 rectangles and add their area
my diagram has 4 ft sidewalk, 75 foot plot, 4 foot sidewalk going left to right.
it also has 4 ft sidewalk, 80 foot plot, 4 foot sidewalk going bottom to top.

Rectangle 1 on the left side of the figure is...
4 * (80 + 4 + 4) = 352
Rectangle 2 on the right hand side is the same size, 352
Rectangle 3, on the bottom of the figure, is 75 * 4 = 300 and rectangle 4 is the same on the top.
352 + 352 + 300 + 300 = 1304

2006-11-02 14:57:19 · answer #2 · answered by DanE 7 · 0 0

easy
(by the way, drawing it will help)

1 compute area of rectangle, including the sidewalk. This is a rectangle of length 80 + 4 + 4 = 88 feet, and width 75 + 4 + 4 = 83 feet. So its area is 7'304 feet squared.

2 compute area of rectangular plot, that's 75 * 80 = 6'000 sq.ft.

3 compute the difference between the two, that's 7'304 - 6'000 = 1'304 sq.ft.

This is the area of the sidewalk

2006-11-02 14:59:19 · answer #3 · answered by AntoineBachmann 5 · 0 0

the plot of ground has an area of 75 x 80 sq ft
the plot including the sidewalk has an area of
(75+4+4)(80+4+4) = 83 x 88 sq ft

the difference is your answer

(83 x 88) - (75 x 80) = 7304 - 6000 = 1304

2006-11-02 14:53:00 · answer #4 · answered by arik p 2 · 0 0

the sidewalk area is the area of the plot plus the sidewalk less the area of the plot.
thus the plot=75*80=6000
the plot plus the s/w =(75+4)*(80+4)=6636
take the two away to give the area of the sidewalk =636

2006-11-02 14:51:54 · answer #5 · answered by jason b 4 · 0 1

the rectangle without the sidewalk is 75*80=6000
with the sidewalk, it is 83*88=7304
7304-6000=1304

2006-11-02 16:13:29 · answer #6 · answered by yupchagee 7 · 0 0

find the area of the plot of ground
A= l8w
A=75*80
A=6000

find the area of the plot of ground and the sidewalk together
A=l*w
A=75+4*80+4
A=6636

Now subtract the area of the ground and sidewalk - the area of the ground and you get the area of the sidewalk

6636-6000=636

2006-11-02 14:53:09 · answer #7 · answered by ineedonebuddy 3 · 0 1

Hint: The outer perimeter of the sidewalk is also a rectangle and it's larger than the plot of land.

Figure out the areas of both rectangles - the sidewalk is one minus the other.

2006-11-02 14:47:44 · answer #8 · answered by Anonymous · 0 0

1176 square feet.

Multiply 75 by 80.
Then subtract the product of 8 more than each of those.
75x80=6000
83x88=7304
7304-6000=1304

2006-11-02 14:54:52 · answer #9 · answered by Anonymous · 0 0

1304

2006-11-02 14:50:19 · answer #10 · answered by Learning 2 · 0 0

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