this would be easier to see if we could draw on here, so bear with me.
The sidewalk is a series of 4 rectangles, each 4' wide and of varying lenghts, to surround the plot of 75' x 80'
the four rectangles then are of lenthgs 75, 75, 80, 80.
This would leave 4' x 4' squares at each corner.
So the area would be:
75*4 + 75*4 + 80*4 + 80*4 + 4*4 + 4*4 + 4*4 + 4*4 = 1304 sq ft
2006-11-02 06:49:01
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answer #1
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answered by disposable_hero_too 6
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Draw a diagram
divide the sidewalk into 4 rectangles and add their area
my diagram has 4 ft sidewalk, 75 foot plot, 4 foot sidewalk going left to right.
it also has 4 ft sidewalk, 80 foot plot, 4 foot sidewalk going bottom to top.
Rectangle 1 on the left side of the figure is...
4 * (80 + 4 + 4) = 352
Rectangle 2 on the right hand side is the same size, 352
Rectangle 3, on the bottom of the figure, is 75 * 4 = 300 and rectangle 4 is the same on the top.
352 + 352 + 300 + 300 = 1304
2006-11-02 14:57:19
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answer #2
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answered by DanE 7
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easy
(by the way, drawing it will help)
1 compute area of rectangle, including the sidewalk. This is a rectangle of length 80 + 4 + 4 = 88 feet, and width 75 + 4 + 4 = 83 feet. So its area is 7'304 feet squared.
2 compute area of rectangular plot, that's 75 * 80 = 6'000 sq.ft.
3 compute the difference between the two, that's 7'304 - 6'000 = 1'304 sq.ft.
This is the area of the sidewalk
2006-11-02 14:59:19
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answer #3
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answered by AntoineBachmann 5
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the plot of ground has an area of 75 x 80 sq ft
the plot including the sidewalk has an area of
(75+4+4)(80+4+4) = 83 x 88 sq ft
the difference is your answer
(83 x 88) - (75 x 80) = 7304 - 6000 = 1304
2006-11-02 14:53:00
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answer #4
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answered by arik p 2
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the sidewalk area is the area of the plot plus the sidewalk less the area of the plot.
thus the plot=75*80=6000
the plot plus the s/w =(75+4)*(80+4)=6636
take the two away to give the area of the sidewalk =636
2006-11-02 14:51:54
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answer #5
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answered by jason b 4
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the rectangle without the sidewalk is 75*80=6000
with the sidewalk, it is 83*88=7304
7304-6000=1304
2006-11-02 16:13:29
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answer #6
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answered by yupchagee 7
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find the area of the plot of ground
A= l8w
A=75*80
A=6000
find the area of the plot of ground and the sidewalk together
A=l*w
A=75+4*80+4
A=6636
Now subtract the area of the ground and sidewalk - the area of the ground and you get the area of the sidewalk
6636-6000=636
2006-11-02 14:53:09
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answer #7
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answered by ineedonebuddy 3
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Hint: The outer perimeter of the sidewalk is also a rectangle and it's larger than the plot of land.
Figure out the areas of both rectangles - the sidewalk is one minus the other.
2006-11-02 14:47:44
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answer #8
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answered by Anonymous
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1176 square feet.
Multiply 75 by 80.
Then subtract the product of 8 more than each of those.
75x80=6000
83x88=7304
7304-6000=1304
2006-11-02 14:54:52
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answer #9
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answered by Anonymous
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1304
2006-11-02 14:50:19
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answer #10
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answered by Learning 2
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