4.Find two consecutive odd integers whose sum is the cube of 4?

Question

x + (x +1) = 43

B.
x + (x +2)3 = 4

C.
x + (x + 2) = 43

D.
none of these

Answer 1

Let the two integers be 'x' and 'x+2'
x + x + 2 = 4^3
2x + 2 = 64
2x = 64 - 2
2x = 62
x = 62/2
x = 31
The integers are 31 and 33.

Answer 2

D, none of these.

the cube of 4 = 4 * 4 * 4 = 64

two consecutive odd numbers have the equation x and x+2 (or x-2). The sum of these gives is x + (x+2).

So you have an equation x + (x+2) = 64.

2x + 2 = 64
2x = 62
x = 31.

The two consecutive odd numbers are 31 and 33.

The correct answer would be:
x (x+2) = 4^3

Answer 3

Two consecutive odd integers may be represented as :

(2x + 1) and (2x + 3)

Adding gives :

(2x + 1) + (2x + 3) = 4^3 = 64

4x + 4 = 64
Dividing through by 4 gives:
x + 1 = 16
Therefore, x = 15

Substituting back shows that 2x + 1 = 31
and 2x + 1 = 33

The 2 numbers are 31 and 33. So answer (D) is correct.

Answer 4

You can figure it out, you know....

Let the first number be x. The second number is x+?...

Their sum is ...?

And that sum should be equal to... ?

By the way, do you have a typo there with the 43's? It should be 4^3 (the cube of 4)

Answer 5

C would be correct, assuming this was supposed to be 4^3 and not 43...

2x + 2 = 64
2x = 62
x = 31
31 and 33

Answer 6

31 and 33

Answer 7

the answer is 31 and 33.
4 cubed is 64.
31+33=64 and they r consecutive odd integars.
not sure how the equations are applicable so me thinks (d).

Answer 8

two odd integers will always equal an even number. no exceptions. 43, being an odd number, its imposible for it to happen