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Cylindrical pulley w/ the following:
mass, M = 6.9 kg
radius, r = 0.811 m
moment of inertia 1/2 Mr^2

is used to lower a bucket (m=2.9 kg) into a well. The bucket starts from rest and falls for 3.3 s, acceleration of graviy is 9.8 m/s^2.

A) What is the linear acceleration of the falling bucket in units of m/s^2?

B) How far does it drop in units of m?

C) What is the angular acceleration of the cylinder in units of rad/s^2?

2006-11-02 04:58:29 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

The bucket fall is determined by the rate the pulley can unwind.
mgr=1/2Mr^2 xAngular acceleration= 1/2Mr^2x a/(2 pi r)

2006-11-02 07:15:41 · answer #1 · answered by meg 7 · 1 0

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