you have four unkown values but only two equations, it's impossible,
2006-11-02 03:38:28
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answer #1
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answered by Anonymous
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i'm at risk of assert, no remember if or no longer this could be splendid, you're the two genuine and incorrect. you're splendid in asserting that ?(p + iq) refers to in basic terms between the sq. roots of (p + iq), it is the comparable for the two genuine and sophisticated numbers for this reason, if i ought to cite your self: If ?(x + iy) = p + iq, then it is likewise - p - iq might mean that p + iq = - p - iq => p = q = 0. in spite of the indisputable fact that, and maximum severely, i don't experience that the notations ?(p + iq) and -?(p + iq) are disambiguous. genuine numbers have the excellence between effective or unfavorable, yet complicated numbers do no longer. in case you know that between the sq. roots of a selection is p + iq, then the different one is going to be -(p + iq) yet utilising the notation ?(p + iq) and -?(p + iq) how will all of us know which one is which? The unfavorable sign is incomprehensible using fact complicated numbers are no longer popular as being effective or unfavorable. enable me to furnish an occasion: 9 - 40i has sq. roots 5 - 4i and -5 + 4i the former sq. root has a useful genuine area yet a unfavorable imaginary area, does this make the selection effective or unfavorable? In different words might you denote 5 - 4i as ?(9 - 40i) or -?(9 - 40i) ? There needs to be a custom prevalent which dictates this, possibly the inspiration with the unfavorable imaginary area must be denoted by capacity of -?(p + iq) i'm no longer conscious of this type of convention and so i won't say to what ?(p + iq) and -?(p + iq) refer, in spite of the indisputable fact that they each and each examine with in basic terms between the complicated sq. roots.
2016-10-21 03:44:02
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answer #2
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answered by ? 4
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My answer to the question is $1 for each item.
2006-11-02 03:49:54
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answer #3
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answered by honeykingz 1
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This is hell of a twister.
Finally I got it right.
The solution is
4.732,1.5,1.268,0.79 all $
You can verify sum of all these,
as well as product comes to 7.11
I will not give you how I went about logically
to get the answer since you did not ask for it.
2006-11-02 04:38:24
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answer #4
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answered by openpsychy 6
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1, 3, 3, and 79 cents
1, 1, 9, and 79 cents
1, 1 and 1 cent and $7.11
2006-11-02 03:43:45
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answer #5
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answered by Anonymous
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There are 4 unknowns & only 2 equations. The problem is underderermined.
2006-11-02 04:58:26
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answer #6
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answered by yupchagee 7
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I agree with Rich Z
2006-11-02 04:07:23
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answer #7
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answered by ctk132 1
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I got the same answer as Rich Z
2006-11-02 03:45:20
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answer #8
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answered by Yuri Slavio 4
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X + Y + Z + W = 7.11
X * Y * Z * W = 7.11
2 equations 4 unknows =
$.79, $2.00, $1.76, and $2.56
2006-11-02 03:40:38
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answer #9
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answered by Grant d 4
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ok... been a long time since I took calculus... I'm stumped... I bet the answer is rediculously easy too... :0(
2006-11-02 03:44:08
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answer #10
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answered by jeep_man129 3
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The prices are $1.20, $1.25, $1.50, and $3.16.
2006-11-02 03:39:11
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answer #11
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answered by Rich Z 7
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