4469
2006-11-02 03:32:42
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answer #1
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answered by lisa 5
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2+2(67+78)30-1 = 2 + (2*145*30) - 1
= 1 + (290*30)
= 1 + 8700
= 8701
2006-11-02 13:02:32
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answer #2
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answered by Akilesh - Internet Undertaker 7
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The order of priority among the operations in solving an expression is given by BEDMAS rule.
The order of priority is
* Bracket
* Exponential
* Division
* Multiplication
* Addition
* Subtraction
Solving the above expression in that order gives the correct result.
2+2(67+78)30-1
= 2+2(145)30-1 ' First solving the bracket
= 2+2*4350-1 ' Solving one multiplication
= 2+8700-1 ' Solving the other multiplication
= 8702-1 ' Next addition
= 8701 ' At last subtraction
Thus u could solve it
Hope u got wat u wanted
2006-11-02 03:43:36
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answer #3
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answered by Arun R 2
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8701, because 67+78 = 145, 145 x 2 x 30 = 8700, 8700 + 2 - 1 = 8701
2006-11-02 03:31:42
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answer #4
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answered by just.ride 1
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2+2(67+78)30-1
2+2*145*30-1=2+8700-1=8701
2006-11-02 05:09:32
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answer #5
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answered by yupchagee 7
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2+2(67+78)30-1=
2+2(145)30-1=
2+2*4350-1=
2+8700-1
8702-1=8701
so the answer is 8701.
hope this helps :)
2006-11-02 03:48:50
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answer #6
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answered by good day :) 2
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2+2(145)30 - 1
= 2+60(145) - 1
= 2+ 8700 - 1
= 8702 - 1
= 8701
2006-11-02 03:34:17
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answer #7
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answered by sugar 2
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2+2=4
(67+78)=145
30-1+29
4(145)29
=16820
=)
2006-11-02 04:37:06
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answer #8
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answered by ♥ mars♥ 4
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8701
2006-11-02 04:40:07
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answer #9
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answered by Anonymous
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8701
2006-11-02 03:40:03
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answer #10
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answered by ddudley543 2
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8701
2006-11-02 03:38:08
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answer #11
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answered by csulbalgebra 2
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