There is a clever kitchen gadget for drying lettuce leaves after you wash them. It consists of a cylindrical container mounted so that it can be rotated about its axis by turning a hand crank. The outer wall of the cylinder is perforated with small holes. You put the wet leaves in the container and turn the crank to spin off the water. The radius of the container is 12 cm. When the cylinder is rotating at 2.0 revolutions per second, what is the magnitude of the centripetal acceleration at the outer wall?
2006-11-02 03:17:17 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Physics
a= r * w^2 = .12 * 2^2 = .12 *4 = .48 m/s^2
2006-11-02 03:28:44 · answer #1 · answered by WildOtter 5 · 0⤊ 4⤋
roughly 18.95m/s/s
but it doesn't seem very clever to just put holes in a cylinder, it will spray water all over the place. Surely the holes should be in an inner cylinder so it just sprays water onto the outer cylinder where it can drain down?
2006-11-02 03:26:17 · answer #2 · answered by Anonymous · 0⤊ 0⤋
A couple of paper towels does it for me. Just press the lettuce leaves between them.
2006-11-02 03:35:54 · answer #3 · answered by PaulCyp 7 · 0⤊ 3⤋
1000 kw per kilometre
2006-11-02 03:19:18 · answer #4 · answered by Anonymous · 0⤊ 0⤋
It's called a lettuce spinner....and it's not that new.what's the question anyways?
2006-11-02 03:24:58 · answer #5 · answered by Starry Eyes 5 · 0⤊ 3⤋
So, why don't you just put your accelerometer in your saladspinner and find out?
2006-11-02 03:21:04 · answer #6 · answered by credo quia est absurdum 7 · 0⤊ 2⤋