solve: 3^x-5 = 17
2006-11-02 02:29:26 · 4 answers · asked by Sherry N 1 in Science & Mathematics ➔ Mathematics
3^x-5 = 17
3^x -5+5 = 17+5
3^x = 22
x = log3 22 = log 22 / log 3 = 2.8135881...
2006-11-02 02:35:39 · answer #1 · answered by PM 3 · 0⤊ 0⤋
Is that 3^(x-5) = 17 or (3^x) - 5 = 17
3^(x-5) = 17
{taking logs on both sides)
log{3^(x-5)} = log{17}
-->
(x-5)log{3} = log{17}
x = log{17}/log{3} + 5
x = 7.5789
or (3^x) - 5 = 17
3^x = 22
log{3^x} = log{22}
-->
xlog{3} = log{22}
x = log{22]/log{3}
x = 2.8136
For rules of Logarithms check source
2006-11-02 10:45:13 · answer #2 · answered by ludacrusher 4 · 0⤊ 0⤋
3^x -5 = 17
3^x = 22
log 3^x = log 22
xlog3 = log 22 [Use property that log x^n = nlog x]
x = (log3)/log 22
2006-11-02 10:38:26 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
http://www.merced.cc.ca.us/faculty/powerd/M2/M2Lec5.htm
read this site you will get your answer.
2006-11-02 10:31:58 · answer #4 · answered by valc 1 · 0⤊ 0⤋