given that LOGa=3.58 and LOGa (y)=4.79, find LOGa(y/x)?

Question

Correction to the problem....given that LOGa(x)=3.58 and LOGa (y)=4.79, find LOGa(y/x)?

Answer 1

LOGa(y/x) = LOGay-LOGax= 4.79-3.58 = 1.21

Answer 2

I suppose you mean LOGa(x)=3.58

You have LOGa(y/x)= LOGa(y) - LOGa(x)
So that makes 1.21

Answer 3

Recall that log (a/b) = log(a) - log(b), and log(ab) = log(a) + log(b)

So, log(a(y/x)) = log(a) + log(y) - log(x)

You've only told us what log(a) and log(y) are, so:

. log(a) + log(y) - log(x) =
. 3.58 + 4.79 - log(x) =
. 8.37 - log(x)

Of course, if you made a typo in your original question, then the answer I gave is incorrect. However, I hope the METHOD that I demonstrated here will help you with your log homework. Good luck!

~ ♥ ~

Answer 4

I smile and say thank you. If i will carry mutually up the braveness, i attempt to declare something great returned to them. humorous undertaking is, I consistently convince myself they weren't being truthful and merely pitying/patronizing me. that's often been that way.

Answer 5

well,
LOGa(y/x) = LOGa(y * x^-1) = LOGa(y) + LOG(x^-1) = LOGa(y) - LOGa(x) = 1.29