the equation is:
y=_x-_
2006-11-01 23:08:20 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The eqaution of the line is
y-y1 =m(x-x1)
y-0 = -3[x-(-4)]
y-0 = -3(x+4)
y= -3x-12
2006-11-01 23:16:31 · answer #1 · answered by Friend 6 · 0⤊ 0⤋
All of the above are wrong, though the top answer is close.
You can use point-slope form any time you have just a point and a slope. Here's in the general form:
(y-y1) = m*(x-x1)
Substituting in (-4,0) for (x1,y1) and -3 for m:
(y-0) = -3 * (x+4)
y = -3x - 12
2006-11-02 07:15:54 · answer #2 · answered by topher8128 2 · 1⤊ 0⤋
Y=mx+c
m=-3
we need to find c
we have (-4,0) lying on the line.
-4=-3*0+c
c=-4
y=-3x-4
2006-11-02 07:43:59 · answer #3 · answered by openpsychy 6 · 0⤊ 0⤋
y= (-4)x - 3
2006-11-02 07:15:44 · answer #4 · answered by musketeer 1 · 0⤊ 1⤋
y=3x-(-12)
2006-11-02 07:13:15 · answer #5 · answered by Anonymous · 0⤊ 0⤋
hmmmm...y = -3x - 4?
2006-11-02 07:13:22 · answer #6 · answered by honeymay 2 · 0⤊ 1⤋