calculate the sodium ion concentration when 70.0ml of 5.5M sodium carbonate is added to 30.0ml of 1.0m sodium?

Question

continue....bicarbonate
no other substance or formula are provided for the problem. looking for a clear explaination.

how is mole of Na calculated out of mole of Na2CO3

Answer 1

Na2CO3 + NaHCO3

moles Na2CO3 = 0.070L * 5.5 mol/L = 0.385 mol
moles of Na+ from Na2CO3 = 0.77 mol
moles NaHCO3 = 0.030L * 1.0 mol/L = 0.030 mol
moles of Na+ from NaHCO3 = 0.03 mol
total moles of Na+ in the solution = 0.80 mol
sodium ion (Na+) concentration = 0.80 mol/0.1L = 8.0M