Algerbra 2 Help?

Question

Can someone teach me how to graph this
Y Is greater then or equal to 1
Y Is greater then -x + 1

Also

x+2y-6z=23
x-3y+z=4
2x+5y-4z=24
Try solving this problem by elmination please.
Thanks ALOT!!!

Answer 1

1) Draw a horizontal line on the graph that crosses the y-axis at y=1. Shade or cross-hatch the area above that line.

2) Draw the graph of the line y = -x + 1. It is a straight line crossing the y-axis at y = +1, and crossing the x axis at x = +1. Values greater than that are above that line.

Multiply the second eq by 6 and add to the first to eliminate z. Multiply the second eq by 4 and add to the third to eliminate z

Now you have 2 eqs in 2 unknowns. Solve the same way: find a factor that will make one of the terms equal and opposite to the same term in the other eq and add them.

Answer 2

For Y is greater than or equal to 1. Draw a solid horizontal line across y=1 and shade above.
For y > -x + 1, since the y-intercept is 1, you might want to start there. so starting from (0,1), to get another point move one unit to the right and move unit down. continue this until you have enough points to draw a line. When you draw the line, make sure is dashed and you shade above too.
______________________
x+2y-6z=23
x-3y+z=4
2x+5y-4z=24

let's eliminate x first.
so multiply -1 to the first equation & the second.
now you have : -x-2y+6z=-23
-x+3y-z=-4
2x+5y-4z=24
let's also eliminate z. multiply the first equation by 2. multiply the sec. by 12. multiply the third by 3. Ummm by then, you should understand what im doing. add them all, adn make sure x and z cancel out. andsolve for y. then substitute to find x and z. well you do the rest :)