Bermuda Triangle if the sides of the triangle have the approximate lengths 842 miles, 921 miles, & 1309 miles?

Question

I have to find the area. This is for my Trigonometry Class. Can you show me how to do this problem?

Answer 1

you could just use heron's formula which is:
if a,b,c are the sides of a triangle then s=(a+b+c)/2
area of a triangle is: square root of s(s-a)(s-b)(s-c)
if its trigo ques and you know the angles then use 0.5bc x sin A
you could use any.

Answer 2

Use Heron's Formula: A = sqrt((s-a)(s-b)(s-c)) where s = (a + b + c)/2 and a, b and c are the lengths of the sides of the triangle. s is called the semiperimeter. In your case

s = (842 + 921 + 1309)/2 = 1536

s - a = 1536 - 842 = 694
s - b = 1536 - 921 = 615
s - c = 1536 - 1309 = 227

A = sqrt((694)(615)(227)) = sqrt(968858700 = 9843.062 sq. mi.

Answer 3

This problem can very easily be done with a geometrical formula according to whichArea of a triangle =root upon s(s-a)(s-b)(s-c) [Remember the root is on the complete expression, where s=half the perimeter of the triangle and a,b and c are the lengths of the sides of the triangle.hence,here s=1536 .a=842,b=921 and c=1309.Putting these va;ues o,we can calculate the area of the triangla and it is found to be 325443 miles^2

Answer 4

You can also solve for the altitude of the triangle and use the formula A = .5*h*b, where b is the base. If the sides of the triangle are a and c, draw the altitude from upper vertex to base. This divides the base into two parts, x and b-x. If the x part is next to side a, the altitude is √[a^2-x^2). From the other side it is [c^2-(b-x)^2]. Equate these to solve for x, then find h.