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I've gone blank! Can someone please shown me how to differentiate this question? Please show working

V= (1/3) pi r^2 h

2006-11-01 17:38:15 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

Depends on what variable you're differentiating with respect to:
dV/dr : 2/3*pi*r*h
dV/dh: 1/3*pi*r^2

2006-11-01 17:42:04 · answer #1 · answered by topher8128 2 · 0 0

dV = (2/3)pirhdr + (1/3) pi r^2dh
dV/dr = (1/3)pir[2h +rdh/dr]
dV/dh = (1/3)pir[2hdr/dh +r]

2006-11-01 17:52:16 · answer #2 · answered by Helmut 7 · 0 0

i think it's
2/3 pi r (dr/dt) (dh/dt)

2006-11-01 17:46:23 · answer #3 · answered by tashita 2 · 0 0

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