the question: In the xy-plane, line j passes through the origin & is perpendicular to the line 4x + y = k, where K is a constant. If the two lines intersect at the point (v,v+1), what is the value of v?
2006-11-01 17:35:42 · 5 answers · asked by vnnd 1 in Science & Mathematics ➔ Mathematics
y=-4x+k is the first line slope =-4= m
second line has a slope-1/m=-1/-4=1/4
second line : y=(1/4)*x+C , but C=0 because line passes through the origin
line is thus y=x/4
substitute v+1 for y and v for x in this equation
v+1=v/4
v=-4/3
2006-11-01 19:37:28 · answer #1 · answered by sydney m 2 · 0⤊ 0⤋
The made from the gradient of two perpendicular lines is continually -a million. Gradient of AB: 3x+4y-16=0 = 4y=-3x+16 = y=(-3x+16)/4 So gradient of AB is -3/4 So -a million=-3/4(gradient of I) Gradient of I= -4/3 so taking the formulation: y-y1=gradient(x-x1) y-3=-4/3(x-7) Now if u confirm this, u receives the answer suggested above
2016-12-05 11:07:00 · answer #2 · answered by geiser 4 · 0⤊ 0⤋
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2014-07-20 19:37:40 · answer #3 · answered by Anonymous · 0⤊ 0⤋
y = -4x + k
y = 4x
2y = k
8x = k
y = k/2 = v + 1
x = k/8 = v
v = k/2 - 1
k/8 = k/2 - 1
k = 4k - 8
3k = 8
k = 8/3
v = k/8
v = 1/3
v + 1 = 4/3
2006-11-01 18:05:06 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋
extremely tough matter. research on yahoo and bing. it will help!
2014-12-04 15:49:17 · answer #5 · answered by Anonymous · 0⤊ 0⤋