what would be the factorial of (2n-1)! (you don't have to put all the terms but give me an idea)
2006-11-01 16:47:18 · 7 answers · asked by Sergio__ 7 in Science & Mathematics ➔ Mathematics
(2n-1) * (2n-2) * (2n-3) * (2n-4)... * 3 * 2 * 1
Just like any other factorial.
2006-11-01 16:50:06 · answer #1 · answered by Pascal 7 · 1⤊ 0⤋
Depends on n. 2n-1 is an odd number, and n has to be at least 1.
If n=1, then (2n-1)! = 1! = 1
If n=2 then (2n-1)! = 3! = 3*2*1
if n=3 then (2n-1)! = 5! = 5*4*3*2*1
etc.
Generally, (2n-1)! = (2n-1)* (2n-2)*(2n-3)*(2n-4)*...*3*2*1
2006-11-02 00:52:49 · answer #2 · answered by iggry 2 · 0⤊ 0⤋
Just take (2n-1) * (2n-2) * (2n-3) * ... * 3 * 2 * 1
Does that help, or did you know that much already and are looking for something else?
2006-11-02 00:50:58 · answer #3 · answered by I ♥ AUG 6 · 0⤊ 0⤋
set k = 2n -1
then (2n-1)! is the same as k!
2006-11-02 00:53:12 · answer #4 · answered by gjmb1960 7 · 0⤊ 0⤋
(2n-1)!=(2n-1) X ((2n-1)!)
2006-11-02 03:26:31 · answer #5 · answered by Anonymous · 0⤊ 0⤋
first substitute the value of n
then start doing your factorials
2006-11-02 00:54:08 · answer #6 · answered by lazareh 2 · 0⤊ 0⤋
Substitute x
2006-11-02 01:01:19 · answer #7 · answered by =P 2 · 0⤊ 0⤋