i think this is an easy question, but...?

Question

I'm drawing a blank on this...

how do I get the number of moles of H20 produced in a rxn of 50 mL of 1.0M HCl and 50mL of 1.0M NaOH?

any help is appreciated:)

Answer 1

Get the chemical equation first:
HCl + NaOH --> NaCl + H2O

Moles of HCl used = (50/1000)dm3 X (1.0mol/dm3) = 0.05 mol
Moles of NaOH used = (50/1000)dm3 x (1.0mol/dm3) = 0.05 mol

From chemical equation, 1 mole of HCl needs 1 mole of NaOH for complete neutralization.
From what you are given, you have the exact amount for complete neutralization (meaning, there is no excess reagents).
From chemical equation again, 1 mole of HCl or NaOH produces 1 mole of water.
Thus you had exactly 0.05 mole of water produced here.
Hope this helps. :)

Answer 2

1.0 M HCL = 1 mole/liter

multiply by 50 ml

Answer 3

You get 1 mole of water for every mole of HCl and NaOH that react. 50 mL times 1M is 0.05 moles each of HCl and NaOH, so you'd get 0.05 moles of water.

Answer 4

50 mmol

The HCl yields 1.0M H+
The NaOH yields 1.0M OH-

The H+ and OH- combine to form 1.0M H2O.

1.0M = 1.0 mol/L
50mL = 0.05L
1.0 mol/L x 0.05L = 0.05 mol = 50 mmol

Answer 5

h20 divided by 50 mL times 1.om + 1.o Na+ answer!