Four candidates run for president of the student council. Three other candidates run for vice-president. How many different ways can the two offices be filled?
Don't get it. HELP
2006-11-01 14:53:05 · 5 answers · asked by hao a 1 in Science & Mathematics ➔ Mathematics
How can I help without giving the answer? Well, anyway, the way to think about this question is, there are four possibilities for president. Each of them has three possibilities for vice-president. So the total number of possible results is 4*3. In the interest of not giving the answer I'll leave it to you to calculate 4*3.
2006-11-01 14:56:10 · answer #1 · answered by Amy F 5 · 0⤊ 0⤋
This is a simple problem in combinations, where the order doesn't matter (pres/vice=vice/pres=one combination). If the order did matter it would be a permutation and more difficult.
So, start with presidential candidate #1 and figure out all the possible combinations there are with each vice presidential candidate (now that's pretty easy), then add all the combinations with the other presidential candidates.
2006-11-01 23:03:14 · answer #2 · answered by hznfrst 6 · 0⤊ 0⤋
think of it this way
the first P can have 3 different choices for VP
the next P also has 3 different choices for VP
and so on and so on
hope that helps :)
2006-11-01 22:55:16 · answer #3 · answered by BABBYK 1 · 0⤊ 0⤋
P can be c1 c2 c3 or c4
VP can be vc1 vc2 or vc3
c1--vc1 vc2 vc3
c2--vc1 vc2 vc3
c3--vc1 vc2 vc3
c4--vc1 vc2 vc3
hope that helps
2006-11-01 23:01:48 · answer #4 · answered by locomexican89 3 · 0⤊ 0⤋
3x4
2006-11-01 22:55:07 · answer #5 · answered by Anonymous · 0⤊ 0⤋