A 1900 kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls 4.00 m before coming into contact with the top of the beam, and it drives the beam 11.0 cm farther into the ground before coming to rest. Using energy considerations, calculate the average force the beam exerts on the pile driver while the pile driver is brought to rest.
2006-11-01 14:27:40 · 3 answers · asked by thewordofrashi 2 in Science & Mathematics ➔ Physics
Energy given = energy absorbed
total travel of pile driver h1 =4.00+0.11=4.11 m
Assume the pile has no mass
energy given = mgh1 = 1900*9.81*4.11
energy absorbed= F * h2 = F * 0.11
F * 0.11 = 1900 * 9.81 * 4.11
F=696,420.82 N
2006-11-01 15:45:18 · answer #1 · answered by Harry 3 · 0⤊ 0⤋
This problem involves Potential Energy and Work, and the principle of conservation of energy.
Potential Energy, PE=Wh, where W is the weight of the pile driver equal to 1900*9.8 and h is the displacement equal to 4.00m. The work done on the beam is equal to F*s, where F is the average force we are looking for, and s is the displacement of 11.00cm or 0.11m.
Based on the principle of conservation of energy, PE=Work:
1900*9.8=F*0.11
F=1900*9.8/0.11
=169,273N.
2006-11-01 14:41:25 · answer #2 · answered by tul b 3 · 0⤊ 1⤋
that relatively relies upon on a great sort of components. do the skaters circulate interior an identical course after the collision or no longer? if no, then you definately take basically the 1st one's mass in any different case the two. is the collsion elastic or inelastic. reckoning on that the equation will exchange.
2016-11-26 22:57:59 · answer #3 · answered by ? 4 · 0⤊ 0⤋