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Question

The force exerted on a spring is proportional to the distance in which the spring stretches from its relaxed positon. Suppose u stretch a spring distance d in inches by applying force F in pounds. For a spring d/f=0.8. you apply forces between 25 and 40 pounds, inclusive. Write a compound inequality describing the stretch of the spring.

Answer 1

d/F = 0.8
so d = 0.8F

When F = 25
d = 20

When F = 40
d = 32

So 20 ≤ d ≤ 32

Answer 2

Hook's law.

d/f is always constant. d = 0.8*f so:

0.8*25< d <0.8*40 , right?