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2006-11-01 13:34:38 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

Enthalpy change of formation of 1 mole of C2H2 is the energy change when 1 mole of it is formed from its elements (2C(s) and H2(g)) in their standard states.

2C(s) + H2(g) ---> C2H2(g)

enthalpy of formation of C2H2=
energy absorbed to break H-H bond
+
energy released to form 1 C=C bond and 4 C-H bonds
= 610 + 4(-410)
= -1030 KJ/mol
(If you are taking A level Chemistry, refer to your data booklet for these values under the section of bond energies)

Hope this helps.

2006-11-01 13:57:52 · answer #1 · answered by ispakles 3 · 0 0

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