For the home described in exercise 15, if the roof is 7 m from peak to?

Question

15)A homeowner wishes to insulate her attic with fiberglass insulation to
conserve energy. The insulation comes in 40-cm wide rolls that are cut to fit between
the rafters in the attic. If the roof is 6 m from peak to eave and the attic space is 2 m high at the peak, how long does each of the pieces of insulation need to be? Round to the nearest tenth.

For the home described in exercise 15, if the roof is 7 m from peak to eave and the attic space is 3 m high at the peak, how long does each of the pieces of insulation need to be? Round to the nearest tenth.

Answer 1

Use the Pythagorean theorem. Drop a perpendicular line from the peak of the roof to the floor of the attic and you have two right triangles. In the first exercise, side A is 2m and the hypotenuse is 6m. In the second part, side A is 3m and the hypotenuse is 7m. Remember to double your answers because you are solving for 1/2 the length.

Answer 2

Sounds like a "homework" help question. Babe, rise over run...and that is all the homeworkhelp you get here. "how can you have your pudding, if you won't eat your meat"