Solve the equation. The square root of 4x + 1, +3 = 0
2006-11-01 12:18:32 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
√(4x + 1) +3 = 0
So √(4x + 1) = -3 (which means that 4x + 1 cannot be real as √N ≥ 0)
So no solution
If you want to solve:
Fnd an x such that one of the square roots of (4x + 1) is - 3,
then 4x + 1 = 9
x = 2
2006-11-01 12:26:28 · answer #1 · answered by Wal C 6 · 0⤊ 1⤋
1. first move the integer 3 to the right side: 4x+1= -3
2. Solve the equation: 4x = -4, x=-1
3 take the square root of the answer: which is the square root of a minus one or "i".
2006-11-01 13:00:54 · answer #2 · answered by Mad Mac 7 · 0⤊ 0⤋
First, move the +3 over to the rigth hand side of the equation.
Sqrt 4x + 1 = -3. Square both sides of the equation.
4x + 1 = 9 Subtract the 1 from both sides.
4x = 8 Divide out the 4 from both sides.
x = 2
2006-11-01 12:26:07 · answer #3 · answered by huckleberry 5 · 0⤊ 0⤋
0 = root(4x+1)+3 -- equation
-3 = root(4x+1) -- subtract 3 from both sides
9 = 4x+1 -- square both sides
8 = 4x -- substract 1 from both sides
2 = x -- divide 4 from both sides
2006-11-01 12:23:45 · answer #4 · answered by Dan C 1 · 0⤊ 0⤋
Its quite sim simple firstly equate 4x+1 =0 by which u will get x= -1/4 then equate 5x-2=0 and u will get x=2/5 ta da
2016-05-23 08:41:22 · answer #5 · answered by Anonymous · 0⤊ 0⤋
x is probably 2
The square root is -3
because (-3)(-3)=9, and -3+3=0
2006-11-01 12:32:15 · answer #6 · answered by Anonymous · 0⤊ 0⤋
1) Subtract 3 both sides: sqr root (4x+1) = -3
2) Square both sides: 4x+1=9
3) Subract 1 both sides: 4x=8
4) Divde 4 both sides: x=2
2006-11-01 12:27:19 · answer #7 · answered by catchu 2 · 0⤊ 0⤋