An Isosceles triangle has a perimeter of 18. Each of the legs is on less than twice the base. How long is each side?
2006-11-01 12:06:09 · 4 answers · asked by SICK MY DUCK! 1 in Science & Mathematics ➔ Mathematics
sorry i made a typo. I meant "one" instead of "on".
2006-11-01 12:15:38 · update #1
You mean "one less."
Call the base x.
Then each leg is 2x-1.
And the perimeter is x + (2x-1) + (2x-1), which equals 18.
Just solve for x and you can calculate the lengths of the sides.
2006-11-01 12:14:12 · answer #1 · answered by actuator 5 · 0⤊ 0⤋
I assume you mean "one" less tha the base. If so then let x = the base. Then each side is 2x-1. So total perimeter is x+ 2(2x-1) =
5x-2
So 5x-2 = 18
5x = 20
x = 4
So each leg is 2*4-1= 7
2006-11-01 12:15:38 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
4, 4 and 10
what did you mean by "is on less that twice the base"?
2006-11-01 12:09:14 · answer #3 · answered by Anonymous · 0⤊ 1⤋
4, 4, 10
2006-11-01 12:12:38 · answer #4 · answered by bethbeth09 1 · 0⤊ 1⤋