In 1999, a group of coin investors bought 50 dimes at an average cost of $8 each, and 100 silver dollars averaging $23 each. In 2000, the investors sold their coins. They made a 20% profit on the dimes and a 10% profit on the silver dollars. How much total profit did they make?
2006-11-01 11:49:14 · 18 answers · asked by lkolka 3 in Science & Mathematics ➔ Mathematics
$310
50 x 8 = 400
100 x 23 = 2300
400 x .20 = $80
2300 x .10 = $230
80 + 230 = $310
2006-11-01 11:51:44 · answer #1 · answered by kikisdragon 3 · 0⤊ 0⤋
Dimes = 400
Dollars= 2300
20% profit for dimes = 400*20 / 100 = 80
10% profit for dollars=2300*10 / 100 = 230
therefore total profit = 80+230=310
2006-11-01 11:54:48 · answer #2 · answered by DonnyD 3 · 0⤊ 0⤋
$310
2006-11-01 11:53:20 · answer #3 · answered by cantstandrudeness 3 · 0⤊ 0⤋
$310
2006-11-01 11:52:07 · answer #4 · answered by WC 7 · 0⤊ 0⤋
$310
2006-11-01 11:51:52 · answer #5 · answered by Anonymous · 0⤊ 0⤋
50 times $8 = $400
100 times $23 = $2300
20% of 400 is $280
10% of 2300 is $230
They made a profit of $310
2006-11-01 11:52:19 · answer #6 · answered by BlondeBarbie 4 · 1⤊ 0⤋
$310.
2006-11-01 11:52:05 · answer #7 · answered by Anonymous · 0⤊ 0⤋
320$ on the dimes and 2070$ on the silver dollars
2006-11-01 11:51:53 · answer #8 · answered by RUNnSHOOT. 3 · 0⤊ 1⤋
I got $310 and I did it all in my head.
2006-11-01 11:59:03 · answer #9 · answered by lynnguys 6 · 0⤊ 0⤋
20% of $8.00 =$1.60 x 50 =$80.00
10% of $23.00= $2.30 x 100 = $230.00
For a total of $310.00
2006-11-01 12:00:36 · answer #10 · answered by READER 1 5 · 0⤊ 0⤋