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a uniform rod of length L is free to pivot around an axis through its upper end. if it is released from rest when horizontal, at what speed is the lower end moving at its lowest point?

(Hint: the gravitational potential energy change is determing by the change in height of the center of gravity.)

2006-11-01 11:33:55 · 1 answers · asked by Trevor M 1 in Science & Mathematics Physics

1 answers

I get V^2 = 3gL

2006-11-01 11:45:07 · answer #1 · answered by Steve 7 · 0 0

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